dailyloe.com – The National Basketball Association announced twelve finalists for the 2025-26 Twyman-Stokes Teammate of the Year Award on Tuesday, April 1, 2026. The list includes notable stars like Jalen Brunson of the New York Knicks and De’Aaron Fox of the San Antonio Spurs. Current NBA players will now vote to select the ultimate winner from this group.
The finalists were selected from both the Eastern and Western Conferences. Six players were chosen from each conference to create the list of twelve. The winner will be chosen solely by a vote among active NBA players.
The award honors the player considered the ideal teammate. It recognizes selfless play and leadership both on and off the court. The recipient also serves as a mentor and dedicated role model.
Finalists are listed alphabetically by their last names. The Eastern Conference finalists include Jalen Brunson and Jayson Tatum. The Western Conference features De’Aaron Fox and Jrue Holiday.
The complete list of finalists was provided by the NBA. It includes Desmond Bane, Pat Connaughton, and Jeff Green. DeAndre Jordan, Duncan Robinson, and Marcus Smart are also finalists.
Garrett Temple and Jaylin Williams round out the list of twelve players. Stephen Curry of the Golden State Warriors won the award for the 2024-25 season. He was last year’s recipient of this prestigious honor.
The Twyman-Stokes Award is an annual honor. It is named after Hall of Famers Jack Twyman and Maurice Stokes. The award celebrates exemplary teamwork and locker room leadership.[]
Source: NBA
